Answered: Ring Ownership: Proximity Based?

Part 1
(May impact a game somewhere some time)
Though there are multiple ways this could occur, I’m just going to explain a [somewhat] simple one.

Red has 30 definite points when time is called. Blue has 27. However, there is a rare situation in which two moveable weighted bases are aimed towards one another (let’s say that they happen to be being bumped by a robot or what have you, though their lips are not touching the ground). Their projections cross at a point which also happens to be the location of a blue ring being held by a red robot (on its way to drop it in the ladder let’s say).

One of the goals has a red ring on it already. The other has a blue ring.

I would assume that the ring would count as scored for whatever goal is closest. Is this correct?

Part 2
(Unlikely to affect any game, so this is more hypothetical in the event that it ever did)
However, there is an almost negligibly small chance of the ring being (so far as the judges can measure) equidistant from the two goals. What happens now? It has to count somewhere, but if it goes to the goal that is already owned by blue, red wins. If it goes to the one owned by red, red’s score goes down to 25, making blue the winner. Which goal does it go on?

Part 1 may occur during some game, and may have an actual impact. I know that Part 2 is splitting hairs, but hypothetically, given the .0000…1% chance of it happening, where would it be scored? Would it be determined by a coin toss/random number generator?

Yes, this is correct.

The referees will use their best judgement to determine which is closer.