I apologize in advance if this is a dumb question. One of my groups built their drivetrain using 3 different sized gears. The driving gears use 84 tooth, but the driven gears are 36 tooth and 60 tooth respectively. So in order, it goes 84 (driving) to 36 (driven) to 60 (driven) to 36 (driven) to 84 (driving). 84 - 36- 60 -36 -84. I’m probably over complicating the question, but hopefully someone can decipher it.
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Depends where you are using the power. If the power is used at the 60t gear, the ratio is 84:60 and the 36 are idlers. If power us used at the 36t’s, the 60 is an idler and the ratio is 84:36.
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If you’re asking how it works with three different-sized gears-
Because the 60-tooth gear is in the center, it acts as an idler, which can be any size, between the 36-tooth gears, both of which are receiving the same amount of force from the 84-tooth gears.
As for actually calculating the gear ratio-
The 60-tooth gear, as an idler, does not affect the ratios of the other gears, so it’s simply 84/36
Take a picture or sketch to illustrate what you are saying it will help us understand what you are trying to say.
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Thanks all! 84/36 answered my question. 60-tooths are the idlers.
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