Inquire about "Delaying the start of a task".

VEX V5 Technical Support
1

In PROS V5 (3.8.0) tutorial “Delaying the start of a task”,
https://pros.cs.purdue.edu/v5/tutorials/topical/notifications.html
the example shows:

void opcontrol() {
    pros::Task delayed_start_task{ [] {
        // block this task until signalled to begin
        while (pros::Task::notify_take(true, TIMEOUT_MAX)) ;    //<===== this line

        while (true) {
            do_task_thing();
            do_another_task_thing();
            pros::delay(20);
        }
    } };

    pros::Controller master{ pros::E_CONTROLLER_MASTER };
    pros::Motor left_motor{ LEFT_MOTOR_PORT };
    pros::Motor right_motor{ RIGHT_MOTOR_PORT };
    while (true) {
        // start the task when the A button is pressed
        if (master.get_digital_new_press(pros::E_CONTROLLER_DIGITAL_A)) {
            delayed_start_task.notify();
        }
        ...
      }
}

But, shouldn’t we use
while (!pros::Task::notify_take(true, TIMEOUT_MAX)) ;
for the blocking instead?
My understanding is when there is no any notification received, the notify_take() will return 0, thus the while loop can continue.

Your comments are appreciated.