That being said, the density of steel is around .291 pounds per cubic inch. An 18â€ť cube (18^3) equates to 5,832 cubic inches of space within the bounds of the cube, and multiplying the amount within the cube by the density gives us (5832*.291) = 1,697.12 pounds of possible material for a robot. HOWEVER, the rules regarding a legal robot state that all materials must be VEX-certified, which dense raw steel is NOT. So, we will have to use 5x25 hole steel plates as a backup. These plates are weighted at 0.327 pounds per plate, and are 0.046â€ť in thickness. This means that we can stack a maximum of 391 plates from the ground to the top of the 18â€ť area allowed. The 5x25 plate are 2.5â€ťx12.5â€ť in total area (from the perimeter) which means that they take up a total of 31.25in^2 of space, and a total of (31.25x0.046)= 1.4375 in^3 of space. This means, in a perfect world, we can cram **4,057 Steel plates** into the possible area. Now, this is fun and all, but it *still doesnâ€™t meet the requirements of a robot.* in order for that (in a loose sense) we need a cortex , a battery, and a key. The cortex takes up 17.15 in^3 of space, or about 12 steel plates worth. The battery takes up 10 steel plates worth, and the key takes up only 1 steel plateâ€™s worth of space. This means, including the 1.13lbs coming from the combination of the necessary items for a robot, we can fit an adjusted total of 4,034 steel plates onto our perfect robot. This means, our perfect robot will weigh (4.034x.327+1.13) pounds, or a total of **1,320.248 pounds.**

TL:DR- my robot this year will be only 4,034 steel plates and a few basic necessities, and will weigh a total of 1,320.248 pounds.