The RobotC compiler is saying I’m diving by zero, but I don’t know why. MogoLiftGearEncoderValue is just a random value the user will put in when using the function and the mogoLiftGearRatio is 12 divided by 60 (12 tooth gear to a 60 tooth gear). Where am I dividing by zero?

If mogoLiftGearRatio is declared an an integer then ROBOTC will understand that it will be zero as 12/60 will round down. ie. when the result of the calculation, 0.2, is converted to an int it will become 0.

Dividing an integer by an integer will not produce fractions, even if normal math would, i.e. the quotient will always be truncated (rounded downwards, essentially “cutting off” a decimal). Say you divide 3 by 2. Ideally, you should get 1.5, but the way C works with integers, that same operation would result in 1, not 1.5. In your case, you’re dividing 12 by 60 and plugging that into a integer variable. Because integer variables don’t have decimals, the C compiler will interpret that as being 0, not 0.2, which is where the zero is coming from. It’s not an error of yours, just the way the C language behaves, specifically in the very nature of int and float data types. To fix that, I suggest using floats instead of ints.

However, if you do 3.0/2 or 3/2.0, the compiler will (“correctly”) read that as 1.5.

It’s “12 / 60;” exactly. What’s in the quotations is exactly what I have for the code. I found a temporary solution where I put the simplified value, so 0.2. It stills boggles me that I can’t have a simple expression. The reason I would like an expression being my other team members need to be able to read the code and input the right values, and they can definitely see what 12 / 60 means (it’s a 5 torque ratio). But they won’t be able to identify 0.2 as quickly.

So when c does math the output of the math is the largest type of the 2 inputs.
12/60 are both ints so it will output an int, which obviously 0.2 becomes 0.

Thats why I said

12/60 is 0
12.0/60 is 0.2

12.0 forces the math to be float /int which outputs a float.